create c function with void argument bug?
Hello,
It seems that this:
CREATE OR REPLACE FUNCTION test_fsync_speed() RETURNS float AS '$libdir/test_fsync_speed','\
test_fsync_speed' LANGUAGE C IMMUTABLE STRICT;
is not equivalent to this (note "void" argument):
CREATE OR REPLACE FUNCTION test_fsync_speed(void) RETURNS float AS '$libdir/test_fsync_speed','\
test_fsync_speed' LANGUAGE C IMMUTABLE STRICT;
Two functions are created.
test=# \df
List of functions
Schema | Name | Result data type | Argument data types | Type
--------+------------------+------------------+---------------------+--------
public | test_fsync_speed | double precision | | normal
public | test_fsync_speed | double precision | void | normal
Furthermore, I can't figure out how to call the "void" argument variant. Why is void accepted as an argument?
create function testvoid(void) returns void as '' LANGUAGE PLPGSQL;
ERROR: PL/pgSQL functions cannot accept type void
I punched the void argument in just by chance- am I just stupid?
Cheers,
M
"A.M." <agentm@themactionfaction.com> writes:
It seems that this:
CREATE OR REPLACE FUNCTION test_fsync_speed() RETURNS float AS '$libdir/test_fsync_speed','\
test_fsync_speed' LANGUAGE C IMMUTABLE STRICT;
is not equivalent to this (note "void" argument):
CREATE OR REPLACE FUNCTION test_fsync_speed(void) RETURNS float AS '$libdir/test_fsync_speed','\
test_fsync_speed' LANGUAGE C IMMUTABLE STRICT;
Why would you think it would be? "void" in SQL doesn't act the same way
as "void" in C, it's an actual type.
regards, tom lane