Using non-grouping-keys at HAVING clause
Hello,
I got a trouble report here:
https://github.com/heterodb/pg-strom/issues/636
It says that PG-Strom raised an error when the HAVING clause used
non-grouping-keys,
even though the vanilla PostgreSQL successfully processed the query.
SELECT MAX(c0) FROM t0 GROUP BY t0.c1 HAVING t0.c0<MIN(t0.c0);
However, I'm not certain what is the right behavior here.
The "c0" column does not appear in the GROUP BY clause, thus we cannot
know its individual
values after the group-by stage, right?
So, what does the "HAVING t0.c0<MIN(t0.c0)" evaluate here?
Best regards,
--
HeteroDB, Inc / The PG-Strom Project
KaiGai Kohei <kaigai@heterodb.com>
On 9/8/23 09:42, Kohei KaiGai wrote:
Hello,
I got a trouble report here:
https://github.com/heterodb/pg-strom/issues/636It says that PG-Strom raised an error when the HAVING clause used
non-grouping-keys,
even though the vanilla PostgreSQL successfully processed the query.SELECT MAX(c0) FROM t0 GROUP BY t0.c1 HAVING t0.c0<MIN(t0.c0);
However, I'm not certain what is the right behavior here.
The "c0" column does not appear in the GROUP BY clause, thus we cannot
know its individual
values after the group-by stage, right?
Wrong. c1 is the primary key and so c0 is functionally dependent on it.
Grouping by the PK is equivalent to grouping by all of the columns in
the table.
--
Vik Fearing
2023年9月8日(金) 19:07 Vik Fearing <vik@postgresfriends.org>:
On 9/8/23 09:42, Kohei KaiGai wrote:
Hello,
I got a trouble report here:
https://github.com/heterodb/pg-strom/issues/636It says that PG-Strom raised an error when the HAVING clause used
non-grouping-keys,
even though the vanilla PostgreSQL successfully processed the query.SELECT MAX(c0) FROM t0 GROUP BY t0.c1 HAVING t0.c0<MIN(t0.c0);
However, I'm not certain what is the right behavior here.
The "c0" column does not appear in the GROUP BY clause, thus we cannot
know its individual
values after the group-by stage, right?Wrong. c1 is the primary key and so c0 is functionally dependent on it.
Grouping by the PK is equivalent to grouping by all of the columns in
the table.
Wow! Thanks, I got the point. Indeed, it is equivalent to the grouping
by all the columns.
--
HeteroDB, Inc / The PG-Strom Project
KaiGai Kohei <kaigai@heterodb.com>