Setting date format for a single output column?
I'd like to get date columns in the results of a query in the
appropriate format (EUROPEAN, GERMAN). I've tried to set DATESTYLE and
it works as far as PgSQL is concerned. Unfortunately, though, this
confuses the date parsing of the O/R-Mapper I'm using[*]. Is there a way
to set the date style/format on a per column basis for the result
returned by a SELECT statement?
Michael
[*] Rails/ActiveRecord. The problem actually lies still deeper in Ruby's
parsedate standard lib method.
--
Michael Schuerig Thinking is trying to make up
mailto:michael@schuerig.de for a gap in one's education.
http://www.schuerig.de/michael/ --Gilbert Ryle
On Wed, Sep 14, 2005 at 02:12:34AM +0200, Michael Schuerig wrote:
I'd like to get date columns in the results of a query in the
appropriate format (EUROPEAN, GERMAN). I've tried to set DATESTYLE and
it works as far as PgSQL is concerned. Unfortunately, though, this
confuses the date parsing of the O/R-Mapper I'm using[*]. Is there a way
to set the date style/format on a per column basis for the result
returned by a SELECT statement?
You could SET datestyle just before issuing the query (so it's not a
per-column answer, but per-query), or use the to_char() function instead
of using the default output.
--
Alvaro Herrera -- Valdivia, Chile Architect, www.EnterpriseDB.com
"Aprende a avergonzarte m�s ante ti que ante los dem�s" (Dem�crito)
On Wednesday 14 September 2005 02:32, Alvaro Herrera wrote:
On Wed, Sep 14, 2005 at 02:12:34AM +0200, Michael Schuerig wrote:
I'd like to get date columns in the results of a query in the
appropriate format (EUROPEAN, GERMAN). I've tried to set DATESTYLE
and it works as far as PgSQL is concerned. Unfortunately, though,
this confuses the date parsing of the O/R-Mapper I'm using[*]. Is
there a way to set the date style/format on a per column basis for
the result returned by a SELECT statement?You could SET datestyle just before issuing the query (so it's not a
per-column answer, but per-query), or use the to_char() function
instead of using the default output.
I had considered that, but I received a better suggestion by private
mail:
Select to_char(date_column, 'dd/mm/yyyy') as date_column
Thanks to all who responded.
Michael
--
Michael Schuerig Face reality and stare it down
mailto:michael@schuerig.de --Jethro Tull, Silver River Turning
http://www.schuerig.de/michael/