regarding join

AKHILESH GUPTA <akhilesh.davim@gmail.com> schrieb:

hi all,
below I have created two tables in pgsql with field name as 'name' and 'id' as
their datatype 'varchar(15)' and 'integer'.

i want the output as:->

... a UNION of this 2 tables:

test=# select * from test1 union select * from test3 order by 2,1;
name | id
-------+----
ab | 1
akhil | 1
b | 2
cd | 2
c | 3
ef | 3
d | 4
gh | 4
e | 5
f | 6
(10 rows)

HTH, Andreas
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On Sat, Mar 25, 2006 at 12:06:34PM +0530, AKHILESH GUPTA wrote:

hi all,
below I have created two tables in pgsql with field name as 'name' and 'id'
as their datatype 'varchar(15)' and 'integer'.

<snip>

Looks like:

select * from test1
UNION ALL
select * from test3;

would be a very good start.
--
Martijn van Oosterhout <kleptog@svana.org> http://svana.org/kleptog/

given this.....
create table AA (id serial,name varchar(15));
create table BB (id serial,name varchar(15));
insert into AA (name) values ('1243f');
insert into AA (name) values ('asdfef');
insert into AA (name) values ('fdbsfd');
insert into AA (name) values ('btgrt');
insert into AA (name) values ('crregsewf');
insert into AA (name) values ('xedrgeef');
insert into BB (name) values ('243f');
insert into BB (name) values ('sdfef');
insert into BB (name) values ('dbsfd');
insert into BB (name) values ('tgrt');
insert into BB (name) values ('rregsewf');
insert into BB (name) values ('edrgeef');

you could try: (if you just need the one column "name")
select name from AA union select name from BB order by name;

a real nice way to go about this is:
create table CC (id serial,name varchar(15));
create table AA() inherits(CC);
create table BB() inherits(CC);
insert into AA (name) values ('1243f');
insert into AA (name) values ('asdfef');
insert into AA (name) values ('fdbsfd');
insert into AA (name) values ('btgrt');
insert into AA (name) values ('crregsewf');
insert into AA (name) values ('xedrgeef');
insert into BB (name) values ('243f');
insert into BB (name) values ('sdfef');
insert into BB (name) values ('dbsfd');
insert into BB (name) values ('tgrt');
insert into BB (name) values ('rregsewf');
insert into BB (name) values ('edrgeef');

=> select * from AA;
id | name
----+-----------
1 | 1243f
2 | asdfef
3 | fdbsfd
4 | btgrt
5 | crregsewf
6 | xedrgeef
(6 rows)

=> select * from BB;
id | name
----+----------
7 | 243f
8 | sdfef
9 | dbsfd
10 | tgrt
11 | rregsewf
12 | edrgeef
(6 rows)

=> select * from CC order by name;
id | name
----+-----------
1 | 1243f
7 | 243f
2 | asdfef
4 | btgrt
5 | crregsewf
9 | dbsfd
12 | edrgeef
3 | fdbsfd
11 | rregsewf
8 | sdfef
10 | tgrt
6 | xedrgeef
(12 rows)

by best regards,

Stefan

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Am Samstag, 25. März 2006 07:36 schrieb AKHILESH GUPTA: