PHP pg_connect
When this fails, I get a useful error print:
$dbconn = pg_connect($connection_str);
Ouput:
Warning: pg_connect() [function.pg-connect]: Unable to connect to
PostgreSQL server: FATAL: password authentication failed for user
"postgres1" in ...
How do I capture this error and handle the printing myself? I want to
be able to know why it failed... ie password in this case.
Thanks,
Vince.
On 17.07.2007 09:13, Vince wrote:
When this fails, I get a useful error print:
$dbconn = pg_connect($connection_str);
Ouput:
Warning: pg_connect() [function.pg-connect]: Unable to connect to
PostgreSQL server: FATAL: password authentication failed for user
"postgres1" in ...How do I capture this error and handle the printing myself? I want to
be able to know why it failed... ie password in this case.
This is a PHP, not a PostgreSQL question.
if (!pg_connect()) {
if (preg_match('/authentication\sfailed/', pg_last_error())) {
echo "Oh dear, you lost your password?\n";
} else if (true) {
echo "OMG, something else went wrong!\n";
}
}
--
Regards,
Hannes Dorbath
On 17.07.2007 09:45, Hannes Dorbath wrote:
This is a PHP, not a PostgreSQL question.
Well, pg_last_error() might not return something in that case. You can
create a custom error handler if the message is important for you.
--
Regards,
Hannes Dorbath
On Jul 17, 2007, at 3:13 AM, Vince wrote:
When this fails, I get a useful error print:
$dbconn = pg_connect($connection_str);
Ouput:
Warning: pg_connect() [function.pg-connect]: Unable to connect to
PostgreSQL server: FATAL: password authentication failed for user
"postgres1" in ...How do I capture this error and handle the printing myself? I want to
be able to know why it failed... ie password in this case.
If I understand correctly:
http://us.php.net/manual/en/function.pg-result-error.php
Show quoted text
Thanks,
Vince.---------------------------(end of
broadcast)---------------------------
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