SQL Query

See if this works; the max aggregate in the subquery could be just about
any function, since it's only going to join to one row.

select max(m1.output_date), m1.parent_id, max(m2.output_id) as
latest_output
from my_table M1 inner join (select output_date, output_id, parent_ID from
my_table) as M2
on m1.output_date = m2.output_date and m1.parent_ID = m2.parent_ID

Where M1.output_date < now()
Group by m1.parent_id

-- Mark

Ashish Karalkar <ashish_postgre@yahoo.co.in>
Sent by: pgsql-novice-owner@postgresql.org
12/13/2007 04:47 AM

To
pgsql-novice@postgresql.org, ashish.karalkar@netcore.co.in
cc

Subject
[NOVICE] SQL Query

Hello List member,
I have a table which ha sfollowing structure

my_table:
(
output_id serial priimary key,
parent_id int,
output_date timesatmp
)

parent_table:

(parent_id int,
parent desc
)

the my_table contains data for previous as well as future output dates.
for single parent there may be multiple rows.

I want to retrieve all the output_id which are having latest output_date
but less than now() (no future output_dates) group by parent_id

Thanks in advance

With Regards
Ashish...

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