E_PARSE error ?
I'm using php5, postgresql 8.3, apache2.2.8, FreeBSD 7.0
I don't understand the message:
*Parse error*: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE,
expecting T_STRING or T_VARIABLE or T_NUM_STRING
the guilty line is:
list($page_id)=sqlget("
select page_id from pages where name='$_SERVER['SCRIPT_NAME']'");
the variable value is "/index.php"
however, at the time of execution this has been cleared
So, the question is - What is the unexpected T_ENCAPSED_AND_WHITESPACE?
and What is actually expected? Are we talking about the content of
$_SERVER['SCRIPT_NAME'] or what is the syntax error? This is within php
code; could it be that the parser is reading this as something else,
like HTML?
I'm lost :((
Hi,
I think, this is the wrong list, it appears to be a PHP error.
Anyway, try to put the global $_SERVER['SCRIPT_NAME'] into {}brackets:
list($page_id)=sqlget("select page_id from pages where
name='{$_SERVER['SCRIPT_NAME']}'");
Hope, You're not lost anymore ...
Ludwig
PJ schrieb:
Show quoted text
I'm using php5, postgresql 8.3, apache2.2.8, FreeBSD 7.0
I don't understand the message:*Parse error*: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE,
expecting T_STRING or T_VARIABLE or T_NUM_STRINGthe guilty line is:
list($page_id)=sqlget("
select page_id from pages where name='$_SERVER['SCRIPT_NAME']'");the variable value is "/index.php"
however, at the time of execution this has been cleared
So, the question is - What is the unexpected T_ENCAPSED_AND_WHITESPACE?
and What is actually expected? Are we talking about the content of
$_SERVER['SCRIPT_NAME'] or what is the syntax error? This is within
php code; could it be that the parser is reading this as something
else, like HTML?
I'm lost :((
On Tue, Jun 3, 2008 at 10:14 AM, PJ <af.gourmet@videotron.ca> wrote:
I'm using php5, postgresql 8.3, apache2.2.8, FreeBSD 7.0
I don't understand the message:*Parse error*: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting
T_STRING or T_VARIABLE or T_NUM_STRINGthe guilty line is:
list($page_id)=sqlget("
select page_id from pages where name='$_SERVER['SCRIPT_NAME']'");
Inside quotes, you need to remove the single quotes around your array
index. Seems wrong, I know, but that's what php says to do. I prefer
to concatenate. so either:
list($page_id)=sqlget("select page_id from pages where
name='$_SERVER[SCRIPT_NAME]'");
list($page_id)=sqlget("select page_id from pages where
name=".$_SERVER['SCRIPT_NAME'].");
are legal.