finding firstname + lastname groups
I have to find the same firstname+ lastname combo in my db and see which
name appears the most so I basically need to do the following:
select name, count(name) from people group by name having count(name)>1
The problem is name is not one column but made up of firstname,
lastname...how do I do this?
Thanks!
On Thu, Jun 19, 2008 at 1:38 PM, blackwater dev <blackwaterdev@gmail.com> wrote:
I have to find the same firstname+ lastname combo in my db and see which
name appears the most so I basically need to do the following:select name, count(name) from people group by name having count(name)>1
The problem is name is not one column but made up of firstname,
lastname...how do I do this?
You can concatenate them. Just use a unique separator like a : symbol
or something. You can do it with a subselect if you like, or in a
single level query.
select last||':'||first, count(last||':'||first) from people group by
last||':'||first having count(last||':'||first) > 1
OR subselect style:
select a.wholename, count(a.wholename) from
(select last||':'||first as wholename from people) as a
group by a.wholename having count(a.wholename) > 1
On Thu, Jun 19, 2008 at 03:38:28PM -0400, blackwater dev wrote:
The problem is name is not one column but made up of firstname,
lastname...how do I do this?
I'd probably do something like:
SELECT firstname, lastname, COUNT(*)
FROM people
GROUP BY firstname, lastname
HAVING COUNT(*) > 1;
Sam
Great, thanks!
On Thu, Jun 19, 2008 at 5:14 PM, Sam Mason <sam@samason.me.uk> wrote:
Show quoted text
On Thu, Jun 19, 2008 at 03:38:28PM -0400, blackwater dev wrote:
The problem is name is not one column but made up of firstname,
lastname...how do I do this?I'd probably do something like:
SELECT firstname, lastname, COUNT(*)
FROM people
GROUP BY firstname, lastname
HAVING COUNT(*) > 1;Sam
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