regexp_replace: LF, CR, or tab

2010/2/27 <seiliki@so-net.net.tw>:

Hi!

I am trying to replace characters '\r', '\n', or '\t' with space character ' '. As an example, I want string "A\t\n\rB" becomes "AB".  The following statement seems to be not working. What mistake have I made?

TIA

CN
========

select regexp_replace(E'A\r\n\tB',E'[\r\n\t]',' ');
 regexp_replace
----------------
 A
        B
(1 row)

Try:
select regexp_replace(E'A\r\n\tB',E'[\r\n\t]',' ','g');

Osvaldo

Just for clarity: In the documentation
(http://www.postgresql.org/docs/8.4/static/functions-matching.html#FUNCTIONS-POSIX-REGEXP)
is mentioned "Flag g causes the function to find each match in the
string, not only the first one, and return a row for each such match. "
So in your example it was only matching \r so A\n\tB was returned

Cheers,

Bastiaan

Osvaldo Kussama wrote: