Custom types as parameter in stored function
Hello to everyone,
I am trying to pass custom types as parameters in stored functions, and I
tried this syntax successfully:
create type myType as (id bigint, name character varying);
create or replace myfunc(obj myType)
returns void as
begin
.......
end;
select myfunc((1, 'foo')::myType;
In this manner, if I understand it, there is a positional assignment of
attribute value: id = 1 and name = foo.
My ask is is there a manner to assing value to attribute of custom type by
name instead by position.
Thanks in advance.
Mephysto.
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Ehmmm, sorry..
Correct syntax for select is:
select myfunc((1, 'foo')::myType);
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On Mon, Jun 27, 2011 at 4:33 AM, mephysto <gennaria@email.it> wrote:
Hello to everyone,
I am trying to pass custom types as parameters in stored functions, and I
tried this syntax successfully:create type myType as (id bigint, name character varying);
create or replace myfunc(obj myType)
returns void as
begin
.......
end;select myfunc((1, 'foo')::myType;
In this manner, if I understand it, there is a positional assignment of
attribute value: id = 1 and name = foo.
My ask is is there a manner to assing value to attribute of custom type by
name instead by position.
You can do it via hstore in 9.0+...just be aware it is slower than the
row constructor method. See the example below -- note CREATE
EXTENSION is a 9.1 feature -- to do it in 9.0 you have to install the
contrib script manually.
postgres=# create extension hstore;
WARNING: => is deprecated as an operator name
DETAIL: This name may be disallowed altogether in future versions of
PostgreSQL.
CREATE EXTENSION
postgres=# create type t as (a int, b text);
CREATE TYPE
postgres=# select populate_record(null::t, 'b=>9, a=>2');
populate_record
-----------------
(2,9)
merlin
Thank you Merlin.
Now, Can I pass the select as an argument of my function?
Or must I do in other manner?
Sorry, but I am a novice.
Best regards.
Mephysto
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