What is *wrong* with this query???
I give! I'm flummoxed!
Here is what I have, 3 tables:
schedule
company building status0
3 x active
4 x active
5 x active
3 x active
3 x active
3 x active
In the end, I want to replace the building id's above. They start out with the non-informative value of '1';
company
id name status
3 x active
4 y active
5 z active
building
id company name
1 3 A active
2 3 B active
3 3 C active
4 4 D active
5 4 E active
6 4 F active
7 5 G active
8 5 H active
9 5 I active
So, every company has 3 schedules. Of the 3, I'd like to select the one with the lowest id.
I'm using postgresql 8.1. Yes, ancient, but I have no choice in this affair.
select schedule.id as sched_id, bld.id as bid
from
schedule
left join company on schedule.company = company.id
left join (select * from building where building.company = company.id order by id limit 1) as bld
where
schedule.status = 'active' and company.status = 'active' and bld.status = 'active';
I get a syntax error on the the "where".
ERROR: syntax error at or near "where" at character ….
LINE 6: where
^
If I leave out the where clause entirely, that's an error also,
ERROR: syntax error at or near ";" at character ….
LINE 5: … as bld ;
^ <it's right under the semicolon>
So, it's expecting ***SOMETHING*** after the "as bld", but it sure isn't going to tell me what.
What am I missing?
On Fri, Nov 4, 2011 at 10:51 PM, Steve Murphy <smurphy@intorrent.com> wrote:
select schedule.id as sched_id, bld.id as bid
from
schedule
left join company on schedule.company = company.id
left join (select * from building where building.company =
company.id order by id limit 1) as bld
where
schedule.status = 'active' and company.status = 'active' and
bld.status = 'active';
Looks like you need an on clause after the second left join.
See embedded note after “as bld”
Dave
From: pgsql-general-owner@postgresql.org [mailto:pgsql-general-owner@postgresql.org] On Behalf Of Steve Murphy
Sent: Saturday, November 05, 2011 12:51 AM
To: pgsql-general@postgresql.org
Subject: [GENERAL] What is *wrong* with this query???
I give! I'm flummoxed!
select schedule.id as sched_id, bld.id as bid
from
schedule
left join company on schedule.company = company.id
left join (select * from building where building.company = company.id order by id limit 1) as bld ****** <-- LEFT JOIN “ON WHAT?”
where
schedule.status = 'active' and company.status = 'active' and bld.status = 'active';
On Friday, November 04, 2011 9:51:14 pm Steve Murphy wrote:
I give! I'm flummoxed!
Here is what I have, 3 tables:
schedule
company building status0
3 x active
4 x active
5 x active
3 x active
3 x active
3 x activeIn the end, I want to replace the building id's above. They start out with
the non-informative value of '1';company
id name status
3 x active
4 y active
5 z activebuilding
id company name
1 3 A active
2 3 B active
3 3 C active
4 4 D active
5 4 E active
6 4 F active
7 5 G active
8 5 H active
9 5 I activeSo, every company has 3 schedules. Of the 3, I'd like to select the one
with the lowest id.I'm using postgresql 8.1. Yes, ancient, but I have no choice in this
affair.select schedule.id as sched_id, bld.id as bid
from
schedule
left join company on schedule.company = company.id
left join (select * from building where building.company =
company.id order by id limit 1) as bld where
schedule.status = 'active' and company.status = 'active' and
bld.status = 'active';I get a syntax error on the the "where".
ERROR: syntax error at or near "where" at character ….
LINE 6: where
^If I leave out the where clause entirely, that's an error also,
ERROR: syntax error at or near ";" at character ….
LINE 5: … as bld ;
^ <it's right under the
semicolon>So, it's expecting ***SOMETHING*** after the "as bld", but it sure isn't
going to tell me what. What am I missing?
on something=something_else
--
Adrian Klaver
adrian.klaver@gmail.com
El 05/11/11 01:51, Steve Murphy escribió:
I give! I'm flummoxed!
Here is what I have, 3 tables:
schedule
company building status0
3 x active
4 x active
5 x active
3 x active
3 x active
3 x active
In the end, I want to replace the building id's above. They start out
with the non-informative value of '1';company
id name status
3 x active
4 y active
5 z active
building
id company name
1 3 A active
2 3 B active
3 3 C active
4 4 D active
5 4 E active
6 4 F active
7 5 G active
8 5 H active
9 5 I active
So, every company has 3 schedules. Of the 3, I'd like to select the
*one* with the lowest id.I'm using postgresql 8.1. Yes, ancient, but I have no choice in this
affair.select schedule.id as sched_id, bld.id as bid
from
schedule
left join company on schedule.company = company.id
left join (select * from building where building.company =
company.id order by id limit 1) as bldwhere
schedule.status = 'active' and company.status = 'active' and
bld.status = 'active';I get a syntax error on the the "where".
ERROR: syntax error at or near "where" at character ….
LINE 6: where
^
If I leave out the where clause entirely, that's an error also,
ERROR: syntax error at or near ";" at character ….
LINE 5: … as bld ;
^ <it's right under the
semicolon>So, it's expecting ***SOMETHING*** after the "as bld", but it sure
isn't going to tell me what.What am I missing?
The join condition maybe?
left join (select....) as bid on ..something....
Show quoted text
On Sat, Nov 5, 2011 at 10:51 AM, Steve Murphy <smurphy@intorrent.com> wrote:
I give! I'm flummoxed!
Here is what I have, 3 tables:
schedule
company building status0
3 x active
4 x active
5 x active
3 x active
3 x active
3 x active
In the end, I want to replace the building id's above. They start out with
the non-informative value of '1';company
id name status
3 x active
4 y active
5 z active
building
id company name
1 3 A active
2 3 B active
3 3 C active
4 4 D active
5 4 E active
6 4 F active
7 5 G active
8 5 H active
9 5 I active
So, every company has 3 schedules. Of the 3, I'd like to select the one with
the lowest id.I'm using postgresql 8.1. Yes, ancient, but I have no choice in this affair.
select schedule.id as sched_id, bld.id as bid
from
schedule
left join company on schedule.company = company.id
left join (select * from building where building.company =
company.id order by id limit 1) as bldwhere
schedule.status = 'active' and company.status = 'active' and
bld.status = 'active';I get a syntax error on the the "where".
ERROR: syntax error at or near "where" at character ….
LINE 6: where
^
If I leave out the where clause entirely, that's an error also,
ERROR: syntax error at or near ";" at character ….
LINE 5: … as bld ;
^ <it's right under the semicolon>
So, it's expecting ***SOMETHING*** after the "as bld", but it sure isn't
going to tell me what.What am I missing?
left join (select * from building where building.company = company.id
order by id limit 1) as bld on (company.id = bld.company)
--
с уважением,
Таир Сабыргалиев
ТОО "BEE Software"
Республика Казахстан, 010000
г.Астана, ул.Сарайшык 34, ВП-27
Тел.: +7 (7172) 56-89-31
Сот.: +7 (702) 2173359
e-mail: tair.sabirgaliev@bee.kz
Tair Sabirgaliev
"BEE Software" Ltd.
Republic of Kazakhstan, 010000
Astana, Sarayshyk str. 34, sect. 27
Tel.: +7 (7172) 56-89-31
Mob.: +7 (702) 2173359
e-mail: tair.sabirgaliev@bee.kz
On 05/11/2011 04:51, Steve Murphy wrote:
select schedule.id as sched_id, bld.id as bid
from
schedule
left join company on schedule.company = company.id
left join (select * from building where building.company =
company.id order by id limit 1) as bld
where
schedule.status = 'active' and company.status = 'active' and
bld.status = 'active';
You're missing the "on" bit after the join, and I think an alias for the
inline view also:
...left join (....) x on (schedule.whatever = x.whatever)
BTW it's a good idea to use explicit column names, not "select *" -
makes for easier bug-finding.
Ray.
--
Raymond O'Donnell :: Galway :: Ireland
rod@iol.ie
Steve,
Op 05-11-11 05:51, Steve Murphy schreef:
I give! I'm flummoxed!
Here is what I have, 3 tables:
schedule
company building status0
3 x active
4 x active
5 x active
3 x active
3 x active
3 x active
In the end, I want to replace the building id's above. They start out with the non-informative value of '1';
company
id name status
3 x active
4 y active
5 z active
building
id company name
1 3 A active
2 3 B active
3 3 C active
4 4 D active
5 4 E active
6 4 F active
7 5 G active
8 5 H active
9 5 I active
So, every company has 3 schedules. Of the 3, I'd like to select the *one* with the lowest id.
I think you mean every company has three buildings...
I'm using postgresql 8.1. Yes, ancient, but I have no choice in this affair.
select schedule.id as sched_id, bld.id as bid
from
schedule
left join company on schedule.company = company.id
left join (select * from building where building.company = company.id order by id limit 1) as bld
where
schedule.status = 'active' and company.status = 'active' and bld.status = 'active';
I get a syntax error on the the "where".
ERROR: syntax error at or near "where" at character ….
LINE 6: where
^
If I leave out the where clause entirely, that's an error also,
ERROR: syntax error at or near ";" at character ….
LINE 5: … as bld ;
^ <it's right under the semicolon>
So, it's expecting ***SOMETHING*** after the "as bld", but it sure isn't going to tell me what.
What am I missing?
I think you actually want to do this:
update schedule set building = (select id from building where company = schedule.company order by id limit 1);
Best,
Antonio.