pgsql age function showing 00:00:00 with year argument

Arup Rakshit wrote:

yelloday-staging::YELLOW=> select id, dob from users;
id | dob
----+---------------------
13 |
9 | 1967-02-13 14:00:00
10 |
11 |
8 | 1977-06-05 14:00:00
15 |
21 |
14 | 2014-05-25 14:00:00
37 |
22 |
26 | 2014-05-06 14:00:00
32 |
35 |
7 |
6 | 2014-05-10 14:00:00
(15 rows)

yelloday-staging::YELLOW=> select date_trunc('year', age(dob)) as age, count(id) from users group by
dob ;
age | count
------------+-------
| 10
00:00:00 | 1
47 years | 1
00:00:00 | 1
37 years | 1
00:00:00 | 1
(6 rows)

Question -

(a) How to convert age to 1 year when age will come as 00:00:00 or calculate the age in years in with
rounding like 0.4, 0.5, 47.3 years like that ?

You mean '0 years', right?

You could use
extract (YEAR FROM date_trunc('year', age(dob)))
to get the number of years as integer.

(b) Why group by didn't group all '00:00:00' ?

Because you grouped by "dob", and the values are different.
You could "GROUP BY 1" to group by the same expression as the first column.

Yours,
Laurenz Albe

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