remark regarding 4.2.13. Row Constructors
The following documentation comment has been logged on the website:
Page: https://www.postgresql.org/docs/18/sql-expressions.html
Description:
Hi,
in
https://www.postgresql.org/docs/current/sql-expressions.html#SQL-SYNTAX-ROW-CONSTRUCTORS
there is:
"The key word ROW is optional when there is more than one expression in the
list."
I think it should be:
"The key word ROW is optional when there are more than zero expressions in
the list."
Test Case:
[postgres@lin5 ~]$ psql mydb
psql (19beta1)
Type "help" for help.
mydb=# select (1);
?column?
----------
1
(1 row)
mydb=# select (1,2);
row
-------
(1,2)
(1 row)
mydb=# select ();
ERROR: syntax error at or near ")"
LINE 1: select ();
^
mydb=# select row();
row
-----
()
(1 row)
mydb=#
Regards
Jochen
On 8 Jun 2026, at 09:42, PG Doc comments form <noreply@postgresql.org> wrote:
in
https://www.postgresql.org/docs/current/sql-expressions.html#SQL-SYNTAX-ROW-CONSTRUCTORS
there is:
"The key word ROW is optional when there is more than one expression in the
list."
I think it should be:
"The key word ROW is optional when there are more than zero expressions in
the list."
"more than zero" sounds a bit odd, my suggestion would be "The key word ROW is
optional when there is one, or more, expressions in the list."
--
Daniel Gustafsson
Daniel Gustafsson <daniel@yesql.se> writes:
On 8 Jun 2026, at 09:42, PG Doc comments form <noreply@postgresql.org> wrote:
in
https://www.postgresql.org/docs/current/sql-expressions.html#SQL-SYNTAX-ROW-CONSTRUCTORS
there is:
"The key word ROW is optional when there is more than one expression in the
list."
I think it should be:
"The key word ROW is optional when there are more than zero expressions in
the list."
"more than zero" sounds a bit odd, my suggestion would be "The key word ROW is
optional when there is one, or more, expressions in the list."
More to the point, the statement is correct as written and either of
these changes would make it wrong. For example, both of these things
produce a two-column composite value:
postgres=# select row(1,2), (1,2);
row | row
-------+-------
(1,2) | (1,2)
(1 row)
postgres=# select pg_typeof(row(1,2)), pg_typeof((1,2));
pg_typeof | pg_typeof
-----------+-----------
record | record
(1 row)
But adding more parentheses around a scalar value does not make
it a composite value:
postgres=# select row(1), (1), ((((1))));
row | ?column? | ?column?
-----+----------+----------
(1) | 1 | 1
(1 row)
postgres=# select pg_typeof(row(1)), pg_typeof((1)), pg_typeof(((((1)))));
pg_typeof | pg_typeof | pg_typeof
-----------+-----------+-----------
record | integer | integer
(1 row)
Maybe there is something we can do to make this clearer, but
the above isn't it.
regards, tom lane