psql variable substitution in plpgsql loop
Hi,
psql fails to populate a table in variable substitution.
the variable being within a plpgsql "goto" loop looks suspicious
thank you
Linux neptune 6.1.0-42-amd64 #1 SMP PREEMPT_DYNAMIC Debian 6.1.159-1
(2025-12-30) x86_64 GNU/Linux
psql (PostgreSQL) 18.2
psql -d bench -v ON_ERROR_STOP=1 --variable=SCHEMANAME=test2 <
create.sql # success
create.sql
begin;
drop table if exists :SCHEMANAME.a_eod100k_s;
CREATE TABLE :SCHEMANAME.a_eod100k_s (
ts timestamp without time zone NOT NULL,
store integer NOT NULL,
dept integer NOT NULL,
category integer NOT NULL,
class integer NOT NULL,
in_stock integer
)
WITH (fillfactor='100');
ALTER TABLE ONLY :SCHEMANAME.a_eod100k_s
ADD CONSTRAINT a_eod100k_s_pk PRIMARY KEY (ts, store, dept, category,
class);
commit;
psql -d bench -v ON_ERROR_STOP=1 --variable=SCHEMANAME=test2 < aa.sql #
fail
ERROR: 42601: syntax error at or near ":"
LINE 18: insert into :SCHEMANAME.a_eod100k_s values(l_ts, s..
aa.sql:
begin;
truncate test.a_eod100k_s;
do
$$
declare
l_ts timestamp := '1970-01-01 00:00:00'::timestamp;
l_rows int4 := 10;
begin
--truncate test.a_eod100k_s;
for store in 1..16
loop
<<bstart>>
for dept in 1..32
loop
for category in 1..64
loop
for class in 1..32
loop
insert into :SCHEMANAME.a_eod100k_s values(l_ts, store, dept,
category, class, 10);
l_rows := l_rows +1;
exit bstart when l_rows > 100000;
end loop;
end loop;
end loop;
l_ts := l_ts +'1 day'::interval;
end loop;
end
$$;
commit;
On Sunday, June 21, 2026, carl clemens <cclemens968@gmail.com> wrote:
psql fails to populate a table in variable substitution.
the variable being within a plpgsql "goto" loop looks suspicious
psql will not modify string literals when performing variable substitution.
David J.
ok, no problem.
Thanks
On Sun, Jun 21, 2026 at 6:17 PM David G. Johnston <
david.g.johnston@gmail.com> wrote:
Show quoted text
On Sunday, June 21, 2026, carl clemens <cclemens968@gmail.com> wrote:
psql fails to populate a table in variable substitution.
the variable being within a plpgsql "goto" loop looks suspiciouspsql will not modify string literals when performing variable substitution.
David J.