Operator '%'
Started by Michael Meskesalmost 27 years ago2 messages
Is there a reason why the special behaviour of '%' was only added to a_expr
and not to b_expr?
Michael
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Re: [HACKERS] Operator '%'
Is there a reason why the special behaviour of '%' was only added to a_expr
and not to b_expr?
Sorry, missed that. Adding now.
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