BUG #2889: Syntax error: WHERE ANY(arrayfield) = N
The following bug has been logged online:
Bug reference: 2889
Logged by: David
Email address: higgsd@gmail.com
PostgreSQL version: 8.1.5
Operating system: OpenBSD 3.9
Description: Syntax error: WHERE ANY(arrayfield) = N
Details:
In reference to the array documentation at:
http://www.postgresql.org/docs/8.1/static/arrays.html#AEN5698
This statement works:
=> SELECT * FROM sal_emp WHERE 10000 = ANY (pay_by_quarter);
But this does not:
=> SELECT * FROM sal_emp WHERE ANY (pay_by_quarter) = 10000;
ERROR: syntax error at or near "ANY" at character ...
The ANY operator has the same problem, others may as well.
While trivial to work around, it is certainly annoying and I can't think of
a good reason why it shouldn't work either way.
"David" <higgsd@gmail.com> writes:
This statement works:
=> SELECT * FROM sal_emp WHERE 10000 = ANY (pay_by_quarter);
But this does not:
=> SELECT * FROM sal_emp WHERE ANY (pay_by_quarter) = 10000;
ERROR: syntax error at or near "ANY" at character ...
This is not a bug, it's the way the syntax works per SQL spec.
ANY must immediately follow the operator it relates to. See
<quantified comparison predicate> syntax in the spec.
regards, tom lane
On 1/13/07, Tom Lane <tgl@sss.pgh.pa.us> wrote:
"David" <higgsd@gmail.com> writes:
This statement works:
=> SELECT * FROM sal_emp WHERE 10000 = ANY (pay_by_quarter);But this does not:
=> SELECT * FROM sal_emp WHERE ANY (pay_by_quarter) = 10000;
ERROR: syntax error at or near "ANY" at character ...This is not a bug, it's the way the syntax works per SQL spec.
ANY must immediately follow the operator it relates to. See
<quantified comparison predicate> syntax in the spec.regards, tom lane
Aha, I see it in the docs now, although it's still rather unintuitive.
Could the appropriate section on arrays be crosslinked to the ANY/ALL
page, to preempt this question in the future?
Thanks.
--david
David Higgs wrote:
On 1/13/07, Tom Lane <tgl@sss.pgh.pa.us> wrote:
"David" <higgsd@gmail.com> writes:
This statement works:
=> SELECT * FROM sal_emp WHERE 10000 = ANY (pay_by_quarter);But this does not:
=> SELECT * FROM sal_emp WHERE ANY (pay_by_quarter) = 10000;
ERROR: syntax error at or near "ANY" at character ...This is not a bug, it's the way the syntax works per SQL spec.
ANY must immediately follow the operator it relates to. See
<quantified comparison predicate> syntax in the spec.regards, tom lane
Aha, I see it in the docs now, although it's still rather unintuitive.
Could the appropriate section on arrays be crosslinked to the ANY/ALL
page, to preempt this question in the future?
I researched this and found this line right above the example you quoted
above:
An alternative method is described in Section 9.17. The above query
could be replaced by:
SELECT * FROM sal_emp WHERE 10000 = ANY (pay_by_quarter);
and section 9.17 is 9.17. Row and Array Comparisons. Not sure we can do
any better than that.
--
Bruce Momjian bruce@momjian.us
EnterpriseDB http://www.enterprisedb.com
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