BUG #5044: error: message type 0x5a arrived from server while idle

Started by vyouzhiover 16 years ago2 messagesbugs
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#1vyouzhi
vyouzhi@gmail.com

The following bug has been logged online:

Bug reference: 5044
Logged by: vyouzhi
Email address: vyouzhi@gmail.com
PostgreSQL version: 8.4.0
Operating system: linux 2.6.25
Description: error: message type 0x5a arrived from server while idle
Details:

hi all:

i use Python and PyGreSQL to link PostgreSQL
but the Python give me the error

the error here :
--------------------------------------------
...
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message type 0x43 arrived from server while idle
message type 0x5a arrived from server while idle
INSERT INTO code (stock_name ,stock_code)values('bbbbb','bbbbb')

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--------------------------------------------

and the PostgreSQL log error like here

-------------------------------------------
...
LOG: unexpected EOF on client connection
...
------------------------------------------

me python code_me.py

--------------------------------------------
#!/usr/bin/env python
#coding=utf-8
import _pg
import threading

con =
_pg.connect(host='127.0.0.1',user='work',dbname='work',passwd='123',port=543
2)

def link_url():
global con
for i in range(100):
print i
stock_sql = "INSERT INTO code (stock_name
,stock_code)values('bbbbb','bbbbb')"
try:
con.query(stock_sql)
except:
print stock_sql

if __name__=='__main__':
for i in range(0,32):
print i
i = threading.Thread(target = link_url)
i.start()

-----------------------------------------------

who can help me ? thanks

#2Alvaro Herrera
alvherre@2ndquadrant.com
In reply to: vyouzhi (#1)
Re: BUG #5044: error: message type 0x5a arrived from server while idle

vyouzhi escribi�:

#!/usr/bin/env python
#coding=utf-8
import _pg
import threading

con =
_pg.connect(host='127.0.0.1',user='work',dbname='work',passwd='123',port=543
2)

def link_url():
global con
for i in range(100):
print i
stock_sql = "INSERT INTO code (stock_name
,stock_code)values('bbbbb','bbbbb')"
try:
con.query(stock_sql)
except:
print stock_sql

if __name__=='__main__':
for i in range(0,32):
print i
i = threading.Thread(target = link_url)
i.start()

-----------------------------------------------

Not a bug. Using a connection from more than one thread is not allowed.

--
Alvaro Herrera http://www.CommandPrompt.com/
PostgreSQL Replication, Consulting, Custom Development, 24x7 support