BUG #5227: please add a divide operator for intervals
The following bug has been logged online:
Bug reference: 5227
Logged by: Michal Pasternak
Email address: michal.dtz@gmail.com
PostgreSQL version: 8.4
Operating system: doesn't matter
Description: please add a divide operator for intervals
Details:
Please add a divide operator for INTERVAL type, if possible.
db=# SELECT '15 seconds'::INTERVAL / '15 seconds'::INTERVAL;
ERROR: operator does not exist: interval / interval
LINE 1: SELECT '15 seconds'::INTERVAL / '15 seconds'::INTERVAL;
^
HINT: No operator matches the given name and argument type(s). You might
need to add explicit type casts.
db=# SELECT EXTRACT(EPOCH FROM '15 seconds'::INTERVAL) / EXTRACT(EPOCH FROM
'15 seconds'::INTERVAL);
?column?
----------
1
(1 row)
"Michal Pasternak" <michal.dtz@gmail.com> writes:
Please add a divide operator for INTERVAL type, if possible.
Given that intervals have multiple subfields, it's far from obvious
what division should mean. What is '1 month' / '1 day'?
db=# SELECT EXTRACT(EPOCH FROM '15 seconds'::INTERVAL) / EXTRACT(EPOCH FROM
'15 seconds'::INTERVAL);
If that's the behavior you want, you already have a way to do it
(and you could wrap that up in a user-defined operator if you chose).
It loses quite a lot of information though, so I doubt we'd want
to enshrine it as the standard definition.
regards, tom lane
1 month / 1 day equals 30.
-----Original Message-----
From: Tom Lane [mailto:tgl@sss.pgh.pa.us]
Sent: Thursday, December 03, 2009 12:46 AM
To: Michal Pasternak
Cc: pgsql-bugs@postgresql.org
Subject: Re: [BUGS] BUG #5227: please add a divide operator for intervals
"Michal Pasternak" <michal.dtz@gmail.com> writes:
Please add a divide operator for INTERVAL type, if possible.
Given that intervals have multiple subfields, it's far from obvious
what division should mean. What is '1 month' / '1 day'?
db=# SELECT EXTRACT(EPOCH FROM '15 seconds'::INTERVAL) / EXTRACT(EPOCH
FROM
'15 seconds'::INTERVAL);
If that's the behavior you want, you already have a way to do it
(and you could wrap that up in a user-defined operator if you chose).
It loses quite a lot of information though, so I doubt we'd want
to enshrine it as the standard definition.
regards, tom lane
