domain over enum problem

Started by Peter Eisentrautover 15 years ago2 messagesbugs
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#1Peter Eisentraut
peter_e@gmx.net

CREATE TYPE zzz_enum AS ENUM ('A', 'B', 'C');
CREATE TABLE zzz_test1 (z zzz_enum);
SELECT * FROM zzz_test1 WHERE z = 'A';

That works. But:

CREATE DOMAIN zzz AS zzz_enum DEFAULT 'A';
CREATE TABLE zzz_test2 (z zzz);
SELECT * FROM zzz_test2 WHERE z = 'A';
ERROR: 42883: operator does not exist: zzz = unknown

#2Tom Lane
tgl@sss.pgh.pa.us
In reply to: Peter Eisentraut (#1)
Re: domain over enum problem

Peter Eisentraut <peter_e@gmx.net> writes:

CREATE TYPE zzz_enum AS ENUM ('A', 'B', 'C');
CREATE TABLE zzz_test1 (z zzz_enum);
SELECT * FROM zzz_test1 WHERE z = 'A';

That works. But:

CREATE DOMAIN zzz AS zzz_enum DEFAULT 'A';
CREATE TABLE zzz_test2 (z zzz);
SELECT * FROM zzz_test2 WHERE z = 'A';
ERROR: 42883: operator does not exist: zzz = unknown

I suppose this is because enforce_generic_type_consistency doesn't smash
domains to base types before checking type_is_enum. I'm a bit hesitant
to change that though. We don't smash to base types before checking if
a domain matches an anyarray, and I seem to recall that that's
intentional.

regards, tom lane