NULL handling in 1D array comparison
postgres=# select version();
version
---------------------------------------------------------------------------------------------------------------------------------
PostgreSQL 13.0 (Ubuntu 13.0-1.pgdg18.04+1) on x86_64-pc-linux-gnu,
compiled by gcc (Ubuntu 7.5.0-3ubuntu1~18.04) 7.5.0, 64-bit
(1 row)
Comparison should return UNKNOWN but it's returning a true.
postgres=# select array[null]=array[null];
?column?
----------
t
(1 row)
postgres=# select array[1, null]=array[1, null];
?column?
----------
t
(1 row)
SQL-99 standard use to say it should come out as UNKNOWN
https://crate.io/docs/sql-99/en/latest/chapters/10.html#comparison
Thanks & Regards,
Manvendra Panwar
Email - manvendra2525@gmail.com
Manvendra <manvendra2525@gmail.com> writes:
Comparison should return UNKNOWN but it's returning a true.
postgres=# select array[null]=array[null];
Yeah, that's intentional, because we have to be able to sort arrays.
Comparison of composites behaves similarly, btw.
SQL-99 standard use to say it should come out as UNKNOWN
We're going to politely ignore the spec on this.
regards, tom lane