Missing type in example
The following documentation comment has been logged on the website:
Page: https://www.postgresql.org/docs/9.4/static/functions-geometry.html
Description:
Hi. You can not select '((1,-1),(-1,1))' # '((1,1),(-1,-1))' without any
type to see example for operator #. In both samples you need also types,
like:
box '((1,-1),(-1,1))' # box '((1,1),(-1,-1))'
# path '((1,0),(0,1),(-1,0))'
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atiris@gmail.com writes:
The following documentation comment has been logged on the website:
Page: https://www.postgresql.org/docs/9.4/static/functions-geometry.html
Description:
Hi. You can not select '((1,-1),(-1,1))' # '((1,1),(-1,-1))' without any
type to see example for operator #. In both samples you need also types,
like:
box '((1,-1),(-1,1))' # box '((1,1),(-1,-1))'
# path '((1,0),(0,1),(-1,0))'
Hmm, you're right. It appears that these examples worked when written,
but that was a long time ago when we had fewer operators named "#".
Thanks for the report!
regards, tom lane
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