LIKE operator
Hi,
With mSQL I used to perform queries like below from within PHP:
select field1, field2 from table1 where field1 like '%$some_variable%'
where the '%' in the LIKE clause matches 0 or more characters of any value.
That is, the query above would match the strings that contain
'$some_variable' OR any string if $some_variable is empty.
For example: my table has two rows with the first record containing
field1='abc' and the second record containing field1='cde'.
If '$some_variable' is empty, then my query would return both rows.
If $some_variable='bc', then the query would return only the row where
field1='abc'.
With PostgreSQL I experience the following:
If '$some_variable' is empty, then my query returns *nothing*.
If $some_variable='bc', then the query would return only the row where
field1='abc'.
As the value of '$some_variable' is to be filled by some user while posting
a form, I don't know in advance if it is going to be empty or not.
How can I make the query results to be exactly as with mSQL without having
to alter my query 'throwing out' every part of the 'where' clause where
'$some_variable' is empty?
TIA,
Paulo
pparola@brazilinfo.com
[Charset iso-8859-1 unsupported, filtering to ASCII...]
Hi,
With mSQL I used to perform queries like below from within PHP:
select field1, field2 from table1 where field1 like '%$some_variable%'
where the '%' in the LIKE clause matches 0 or more characters of any value.
That is, the query above would match the strings that contain
'$some_variable' OR any string if $some_variable is empty.For example: my table has two rows with the first record containing
field1='abc' and the second record containing field1='cde'.If '$some_variable' is empty, then my query would return both rows.
If $some_variable='bc', then the query would return only the row where
field1='abc'.With PostgreSQL I experience the following:
If '$some_variable' is empty, then my query returns *nothing*.
If $some_variable='bc', then the query would return only the row where
field1='abc'.As the value of '$some_variable' is to be filled by some user while posting
a form, I don't know in advance if it is going to be empty or not.How can I make the query results to be exactly as with mSQL without having
to alter my query 'throwing out' every part of the 'where' clause where
'$some_variable' is empty?
With 6.5 beta, I get:
test=> create table t (x text);
CREATE
test=> insert into t values ('abc');
INSERT 18697 1
test=> insert into t values ('bcd');
INSERT 18698 1
test=> select * from t where x like '%%';
x
---
abc
bcd
(2 rows)
Not sure what 6.4 does, but I will say I overhauled the LIKE code in
6.5beta.
--
Bruce Momjian | http://www.op.net/~candle
maillist@candle.pha.pa.us | (610) 853-3000
+ If your life is a hard drive, | 830 Blythe Avenue
+ Christ can be your backup. | Drexel Hill, Pennsylvania 19026
If it really has to do with the version, then I cannot do anything about
it...
My ISP runs version 6.3, and they will always be a little bit not
up-to-date.
Thanks a lot,
Paulo
pparola@brazilinfo.com
-----Mensagem original-----
De: Bruce Momjian <maillist@candle.pha.pa.us>
Para: PostgreSQL <pgsql@brazilinfo.com>
Cc: pgsql-general@postgreSQL.org <pgsql-general@postgreSQL.org>
Data: Sexta-feira, 23 de Abril de 1999 17:56
Assunto: Re: [GENERAL] LIKE operator
[Charset iso-8859-1 unsupported, filtering to ASCII...]
Hi,
With mSQL I used to perform queries like below from within PHP:
select field1, field2 from table1 where field1 like '%$some_variable%'
where the '%' in the LIKE clause matches 0 or more characters of any
value.
That is, the query above would match the strings that contain
'$some_variable' OR any string if $some_variable is empty.For example: my table has two rows with the first record containing
field1='abc' and the second record containing field1='cde'.If '$some_variable' is empty, then my query would return both rows.
If $some_variable='bc', then the query would return only the row where
field1='abc'.With PostgreSQL I experience the following:
If '$some_variable' is empty, then my query returns *nothing*.
If $some_variable='bc', then the query would return only the row where
field1='abc'.As the value of '$some_variable' is to be filled by some user while
posting
a form, I don't know in advance if it is going to be empty or not.
How can I make the query results to be exactly as with mSQL without
having
Show quoted text
to alter my query 'throwing out' every part of the 'where' clause where
'$some_variable' is empty?With 6.5 beta, I get:
test=> create table t (x text);
CREATE
test=> insert into t values ('abc');
INSERT 18697 1
test=> insert into t values ('bcd');
INSERT 18698 1
test=> select * from t where x like '%%';
x
---
abc
bcd
(2 rows)Not sure what 6.4 does, but I will say I overhauled the LIKE code in
6.5beta.-- Bruce Momjian | http://www.op.net/~candle maillist@candle.pha.pa.us | (610) 853-3000 + If your life is a hard drive, | 830 Blythe Avenue + Christ can be your backup. | Drexel Hill, Pennsylvania 19026
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