convert integer to interval ?
Sorry, I dont get familar with timefunctions in 7.3.2. I just
upgraded and I need a function that adds a given interval in days to a
given timestamp.
something like
select current_timestamp+interval '7 days';
in my table the 7 is given as integer. And I dont get the conversion
from this integer to interval where the integernumber is in days.
thnx,
peter
--
mag. peter pilsl
IT-Consulting
tel: +43-699-1-3574035
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pilsl@goldfisch.at
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pilsl@goldfisch.at wrote:
Sorry, I dont get familar with timefunctions in 7.3.2. I just
upgraded and I need a function that adds a given interval in days to a
given timestamp.something like
select current_timestamp+interval '7 days';in my table the 7 is given as integer. And I dont get the conversion
from this integer to interval where the integernumber is in days.
Is there any reason why you can't do:
sprintf(buf,"select current_timestamp+interval '%d days'",int_days);
Magnus
On Sat, 8 Feb 2003 pilsl@goldfisch.at wrote:
Sorry, I dont get familar with timefunctions in 7.3.2. I just
upgraded and I need a function that adds a given interval in days to a
given timestamp.something like
select current_timestamp+interval '7 days';in my table the 7 is given as integer. And I dont get the conversion
from this integer to interval where the integernumber is in days.
One way is to make an interval string and cast it (something like)
select current_timestamp + CAST(num || ' days' AS interval);
"Magnus Naeslund(f)" <mag@fbab.net> writes:
pilsl@goldfisch.at wrote:
something like
select current_timestamp+interval '7 days';
Is there any reason why you can't do:
sprintf(buf,"select current_timestamp+interval '%d days'",int_days);
Also, if you really only want the result to the nearest day, date
arithmetic (as opposed to timestamp arithmetic) works the way you want.
For example,
regression=# select current_date, current_date + 7;
date | ?column?
------------+------------
2003-02-08 | 2003-02-15
(1 row)
regards, tom lane