Re: GROUPing problem
I think this should work:
select date_part('month', signedup) as month,date_part('year', signedup)
as year, count(*) from member group by year,month order by year,month
Hope, it helps...
Dima
Kurt Overberg wrote:
Show quoted text
Hi all, I'm hoping someone can shed some light on something for me.
This will most likely be one of those newbie questions, but I'm having
a real hard time understanding this, and would appreciate some help.I'm trying to build a query to return number of records per month. My
query looks like:select date_part('month', signedup), count(*) from member group by
date_part;...this works great, it returns:
date_part | count
-----------+-------
1 | 842
2 | 205
9 | 863
10 | 770
11 | 687
12 | 832...however, the data is from september to february, so I'd like to
sort by year, to get the months in the proper order - so when I try:date_part('month', signedup) as month, count(*) from member group by
date_part order by date_part('year', signedup) asc;I get:
ERROR: Attribute member.signedup must be GROUPed or used in an
aggregate functionI don't understand why just adding the 'order by' makes
member.signedup suddenly need to be included in the group by section.
I want the same results, I just want them ordered differently. Plus,
if I do include member.signedup, it ruins my aggregation.I'm using postgresql 7.2 on debian.
Any thoughts would be appreciated. Thanks!
/kurt
Import Notes
Reply to msg id not found: cfa5bc92.0302220609.5f97492a@posting.google.comReference msg id not found: cfa5bc92.0302220609.5f97492a@posting.google.com