Lexical question...
Hello,
I have a table with a timestamp column and I want to set this to a value
of now() - a random number of days between 0 and 45 for each row... I've
tried to do this a bunch of different ways and can't figure it out...
Here is my latest version:
update sometable set entered_dt = now() - interval round(random()*45)||'
days';
Any ideas on the proper way to accomplish this?
Thanks!
- Greg
Err, I just read my latest digest and saw the solution:
update datafrenzy.jobdata set entered_dt= now() - CAST(round(random()*45)
|| ' days' AS interval);
- Greg
Show quoted text
Hello,
I have a table with a timestamp column and I want to set this to a value
of now() - a random number of days between 0 and 45 for each row... I've
tried to do this a bunch of different ways and can't figure it out...
Here is my latest version:update sometable set entered_dt = now() - interval round(random()*45)||'
days';Any ideas on the proper way to accomplish this?
Thanks!
- Greg
On Nov 23, 2004, at 5:33 AM, Net Virtual Mailing Lists wrote:
I have a table with a timestamp column and I want to set this to a
value
of now() - a random number of days between 0 and 45 for each row...
I've
tried to do this a bunch of different ways and can't figure it out...
Here is my latest version:update sometable set entered_dt = now() - interval
round(random()*45)||'
days';
Try
select now() - ((round(random()*45))::text || ' days')::interval;
Best,
John DeSoi, Ph.D.
http://pgedit.com/
Power Tools for PostgreSQL
On Tue, Nov 23, 2004 at 09:03:26AM -0500, John DeSoi wrote:
select now() - ((round(random()*45))::text || ' days')::interval;
Or one of the following (add round() if desired):
select now() - 45 * random() * interval'1 day';
select now() - random() * interval'45 day';
--
Michael Fuhr
http://www.fuhr.org/~mfuhr/